Proof of Sublogarithmic reconstruction

groundedproofs/Lax100001Proofs/Results.lean · lax-100001

What this proof establishes

no assumptions

Assuming the claims on the left, the claim on the right holds — checked by the archive's pipeline. Proof code is not displayed here.

In the paper

  • page 18 of this submission's paper

Description

Rule U reads the word in rounds and then completes it, its answers determine the word, and it asks at most 250log⁡2n⋅log⁡2log⁡2n250\sqrt{\log_2 n \cdot \log_2 \log_2 n} queries for n≥4n \ge 4.